Example:
N = 3
= 10.60
= 11.91
= y3 = 11.09
y = 11.20
Example:
N = 3
= 10.60
= 11.91
= y3 = 11.09
y = 11.20
[SIGMA]y = 0.6619
Example:
N = 3
= 10.60
= 11.91
= y3 = 11.09
= 11.21
Example:
= 1800.0
N = 3
= 1806.4
= 1803.1
= 1798.9
accuracy = 2.8
Example:
= 1205.3
Y = 1123.8
[SIGMA]ref = 9.399
[SIGMA]y = 10.583
= 11
N = 7
t = 16.63
[SIGMA]ref = 9.399
[SIGMA]y = 10.583
= 11
N = 7
v = 11.76
Example 1:
[EPSILON] = -0.12580
N = 16
[SIGMA][EPSILON] = 0.04837
t = 10.403
v = N-1
Example 2:
N = 16
v = 16-1
v = 15
Table 1 of § 1065.602 -Critical t Values Versus Number of Degrees of Freedom, va
v | Confidence | |
90% | 95% | |
1 | 6.314 | 12.706 |
2 | 2.920 | 4.303 |
3 | 2.353 | 3.182 |
4 | 2.132 | 2.776 |
5 | 2.015 | 2.571 |
6 | 1.943 | 2.447 |
7 | 1.895 | 2.365 |
8 | 1.860 | 2.306 |
9 | 1.833 | 2.262 |
10 | 1.812 | 2.228 |
11 | 1.796 | 2.201 |
12 | 1.782 | 2.179 |
13 | 1.771 | 2.160 |
14 | 1.761 | 2.145 |
15 | 1.753 | 2.131 |
16 | 1.746 | 2.120 |
18 | 1.734 | 2.101 |
20 | 1.725 | 2.086 |
22 | 1.717 | 2.074 |
24 | 1.711 | 2.064 |
26 | 1.706 | 2.056 |
28 | 1.701 | 2.048 |
30 | 1.697 | 2.042 |
35 | 1.690 | 2.030 |
40 | 1.684 | 2.021 |
50 | 1.676 | 2.009 |
70 | 1.667 | 1.994 |
100 | 1.660 | 1.984 |
1000+ | 1.645 | 1.960 |
a Use linear interpolation to establish values not shown here.
Example:
F = 1.268
Example:
N = 6000
= 2045.8
y = 1050.1
= 2045.0
= 1055.3
= 1.0110
Example:
N = 6000
= 2045.8
= 2045.0
= 1.0110
Example:
y = 1050.1
= 1.0110
= 1055.3
= 1050.1 - (1.0110 · 1055.3)
= -16.8083
Example:
N = 6000
= 2045.8
= -16.8083
= 1.0110
= 2045.0
= 5.348
Example:
N = 6000
= 2045.8
= 1.0110
= 2045.0
= 5.347
Example:
N = 6000
= 2045.8
= -16.8083
= 1.0110
= 2045.0
y = 1480.5
Pfrict. Use this information along with the engine displacement volume, Vdisp, an approximate volumetric efficiency, [ETA]V, and the number of engine strokes per power stroke (two-stroke or four-stroke), Nstroke, to estimate the maximum raw exhaust molar flow rate, nexhmax.
Example:
= 2.5 g/(kW·hr)
= 11.883 kW·hr
= 46.0055 g/mol = 46.0055·10-6 g/[MICRO]mol
[DELTA]tdutycycle = 20 min = 1200 s
= 35.65 kW
= 15%
= 125 kW
= 300 kPa = 300000 Pa
= 3.0 l = 0.0030 m3/r
= 2800 r/min = 46.67 r/s
= 4
[ETA]V = 0.9
R = 8.314472 J/(mol·K)
= 348.15 K
Example:
= 1.5 g/(kW·hr)
= 5.389 kW·hr
= 13.875389 g/mol = 13.875389·10-6 g/[MICRO]mol
= 6.021 mol/s
[DELTA]tdutycycle = 30 min = 1800 s
= 53.8 [MICRO]mol/mol
40 C.F.R. §1065.602